[CSR] unknown csr names now fail without exception

kernel-mode
Anton Lydike 4 years ago
parent c4cd83701f
commit 291f44a192

@ -65,20 +65,22 @@ class CSR:
def __init__(self): def __init__(self):
self.regs = defaultdict(lambda: 0) self.regs = defaultdict(lambda: 0)
self.listeners = defaultdict(lambda: (lambda x, y: ())) self.listeners = defaultdict(lambda: (lambda x, y: None))
def set(self, addr: Union[str, int], val: int): def set(self, addr: Union[str, int], val: int):
if isinstance(addr, str): if isinstance(addr, str):
if not addr in self.name_to_addr: if addr not in self.name_to_addr:
print("Unknown CSR register {}".format(addr)) print("Unknown CSR register {}".format(addr))
return
addr = self.name_to_addr[addr] addr = self.name_to_addr[addr]
self.listeners[addr](self.regs[addr], val) self.listeners[addr](self.regs[addr], val)
self.regs[addr] = val self.regs[addr] = val
def get(self, addr: Union[str, int]): def get(self, addr: Union[str, int]):
if isinstance(addr, str): if isinstance(addr, str):
if not addr in self.name_to_addr: if addr not in self.name_to_addr:
print("Unknown CSR register {}".format(addr)) print("Unknown CSR register {}".format(addr))
return
addr = self.name_to_addr[addr] addr = self.name_to_addr[addr]
return self.regs[addr] return self.regs[addr]

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